java.lang.NumberFormatException: For input string: "11000000000000000000000000000011"

Coderanch | nirjari patel | 6 years ago
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Root Cause Analysis

  1. java.lang.NumberFormatException

    For input string: "11000000000000000000000000000011"

    at java.lang.NumberFormatException.forInputString()
  2. Java RT
    Integer.parseInt
    1. java.lang.NumberFormatException.forInputString(Unknown Source)
    2. java.lang.Integer.parseInt(Unknown Source)
    2 frames
  3. package1
    JigBitOp.main
    1. package1.JigBitOp.main(JigBitOp.java:25)
    1 frame