java.lang.NumberFormatException: For input string: "11000000000000000000000000000011"

Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips

,

You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

,

Java does not handle IPv6 nameservers before 1.8.0_60. Upgrade to the latest JVM.

Solutions on the web

via Coderanch by nirjari patel, 1 year ago
For input string: "11000000000000000000000000000011"
via Google Groups by Puja Gupta, 1 year ago
For input string: "--conf"
via Stack Overflow by jmissao
, 2 years ago
via Stack Overflow by Unknown author, 2 years ago
java.lang.NumberFormatException: For input string: "11000000000000000000000000000011"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at package1.JigBitOp.main(JigBitOp.java:25)

Users with the same issue

Samebug visitor profile picture
Unknown user
Once, 5 months ago
Samebug visitor profile picture
Unknown user
Once, 1 year ago
Samebug visitor profile picture
Unknown user
Once, 1 year ago
Samebug visitor profile picture
Unknown user
Once, 1 year ago
Samebug visitor profile picture
Unknown user
Once, 1 year ago
266 more bugmates

Know the solutions? Share your knowledge to help other developers to debug faster.