java.lang.NumberFormatException: For input string: "6 .136"

Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips

0
rp, 9 months ago
You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.
6
rp, 1 year ago
Java does not handle IPv6 nameservers before 1.8.0_60. Upgrade to the latest JVM.

Solutions on the web

cant find symbol: variable octet1

For input string: "6 .136"

UDP Packet content changes while transmitting

For input string: "6002��"

Parse an int from a string

For input string: "shirt "

JobConf.parseMaximumHeapSizeMB() fails to parse value greater than 2GB expressed in bytes

For input string: "2147483648"

Re: Error using xml-rpc

For input string: "Client"

java.lang.NumberFormatException: For input string: "6.136"	at java.lang.NumberFormatException.forInputString(Unknown Source)	at java.lang.Integer.parseInt(Unknown Source)	at java.lang.Integer.parseInt(Unknown Source)	at IpAddress.getOctet3(IpAddress.java:75)	at BenHultinProg1.main(BenHultinProg1.java:16)