java.lang.NumberFormatException: For input string: ""

Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips

,

You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

,

Java does not handle IPv6 nameservers before 1.8.0_60. Upgrade to the latest JVM.

Solutions on the web

via Kuali JIRA by Nina Gelderbloem, 1 year ago
For input string: "qwe"
via Oracle Community by 807569, 1 year ago
via Stack Overflow by cyber-monk
, 2 years ago
For input string: "abcdef01"
java.lang.NumberFormatException: For input string: ""
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
at java.lang.Integer.parseInt(Integer.java:470)

Users with the same issue

Samebug visitor profile picture
Unknown user
Once, 1 week ago
2 times, 1 week ago
Samebug visitor profile picture
Unknown user
Once, 1 month ago
Once, 1 month ago
5 times, 4 months ago
265 more bugmates

Know the solutions? Share your knowledge to help other developers to debug faster.