java.util.InputMismatchException: For input string: "12345"

Coderanch | Steve Luke | 8 years ago
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Root Cause Analysis

  1. java.util.InputMismatchException

    For input string: "12345"

    at java.util.Scanner.nextInt()
  2. Java RT
    Scanner.nextInt
    1. java.util.Scanner.nextInt(Scanner.java:2097)
    1 frame
  3. splitdigits
    SplitDigits.main
    1. splitdigits.SplitDigits.main(SplitDigits.java:21)
    1 frame