java.lang.NumberFormatException: For input string: "b"

Coderanch | Alex Reynders | 8 years ago
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    Coderanch | 8 years ago | Alex Reynders
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Root Cause Analysis

  1. java.lang.NumberFormatException

    For input string: "b"

    at java.lang.NumberFormatException.forInputString()
  2. Java RT
    Long.parseLong
    1. java.lang.NumberFormatException.forInputString(Unknown Source)
    2. java.lang.Long.parseLong(Unknown Source)
    3. java.lang.Long.parseLong(Unknown Source)
    3 frames
  3. org.Java.Instructor
    Project.main
    1. org.Java.Instructor.Project.hexadecimalEquivalent1(Project.java:86)
    2. org.Java.Instructor.Project.Calculator(Project.java:271)
    3. org.Java.Instructor.Project.main(Project.java:329)
    3 frames