java.lang.NumberFormatException: For input string: "9044150091"

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    Coderanch | 10 years ago | James Brooks
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Root Cause Analysis

  1. java.lang.NumberFormatException

    For input string: "9044150091"

    at java.lang.NumberFormatException.forInputString()
  2. Java RT
    Integer.parseInt
    1. java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
    2. java.lang.Integer.parseInt(Integer.java:459)
    3. java.lang.Integer.parseInt(Integer.java:497)
    3 frames
  3. Unknown
    phoneBook.main
    1. phoneBook.setNum(phoneBook.java:25)
    2. phoneBook.main(phoneBook.java:36)
    2 frames