java.lang.NumberFormatException: For input string: "2147483648"

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You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

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via GitHub by jlg
, 1 year ago
via cloudera.com by Unknown author, 1 year ago
via Eclipse Bugzilla by Darin_Swanson, 1 year ago
For input string: "osgi.bundles.defaultStartLevel"
via Google Groups by Longzhi Tan, 10 months ago
via Google Groups by adam, 2 years ago
For input string: "hello"
java.lang.NumberFormatException: For input string: "2147483648"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
at java.lang.Integer.parseInt(Integer.java:463)
at java.lang.Integer.parseInt(Integer.java:497)
at py4j.Protocol.getInteger(Protocol.java:164)
at py4j.Protocol.getObject(Protocol.java:215)
at py4j.commands.AbstractCommand.getArguments(AbstractCommand.java:107)
at py4j.commands.CallCommand.execute(CallCommand.java:79)
at py4j.GatewayConnection.run(GatewayConnection.java:173)
at java.lang.Thread.run(Thread.java:619)

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