java.lang.NumberFormatException

For input > string: "8888 --address=0.0.0.0" > > at > java.lang.NumberFormatException.forInputString(NumberFormatException.java:65) >

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  • via Unknown by Alejandro Marcos,
  • via Stack Overflow by Leonardo
    ,
  • Stack trace

    • java.lang.NumberFormatException: For input > string: "8888 --address=0.0.0.0" > > at > java.lang.NumberFormatException.forInputString(NumberFormatException.java:65) > at java.lang.Integer.parseInt(Integer.java:492)

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