java.lang.NumberFormatException: For input > string: "8888 --address=0.0.0.0" > > at > java.lang.NumberFormatException.forInputString(NumberFormatException.java:65) >

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Root Cause Analysis

  1. java.lang.NumberFormatException

    For input > string: "8888 --address=0.0.0.0" > > at > java.lang.NumberFormatException.forInputString(NumberFormatException.java:65) >

    at java.lang.Integer.parseInt()
  2. Java RT
    Integer.parseInt
    1. java.lang.Integer.parseInt(Integer.java:492)
    1 frame