java.lang.StringIndexOutOfBoundsException: String index out of range: 0 R - Square Root N - Natural Log X - Exit the program Enter a function

Stack Overflow | Kelbin Gomez | 7 months ago
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    While-loop with a switch statement, not looping correctly as intended

    Stack Overflow | 7 months ago | Kelbin Gomez
    java.lang.StringIndexOutOfBoundsException: String index out of range: 0 R - Square Root N - Natural Log X - Exit the program Enter a function
  2. 0
    samebug tip
    Thrown by String methods to indicate that an index is either negative or greater than the size of the string. For some methods such as the charAt method, this exception also is thrown when the index is equal to the size of the string.
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    java.lang.StringIndexOutOfBoundsException: String index out of range: 0
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    IOOBE

    GitHub | 3 years ago | meysholdt
    java.lang.StringIndexOutOfBoundsException: String index out of range: 156

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Root Cause Analysis

  1. java.lang.StringIndexOutOfBoundsException

    String index out of range: 0 R - Square Root N - Natural Log X - Exit the program Enter a function

    at java.lang.String.charAt()
  2. Java RT
    String.charAt
    1. java.lang.String.charAt(String.java:658)
    1 frame
  3. assigment9
    Assigment9.main
    1. assigment9.Assigment9.main(Assigment9.java:110)
    1 frame