java.lang.NumberFormatException: For input string: "ABC"

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You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

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Java does not handle IPv6 nameservers before 1.8.0_60. Upgrade to the latest JVM.

Solutions on the web

via GitHub by kbthomas59
, 1 year ago
For input string: "ABC"
via Eclipse Bugzilla by sbalusani, 1 year ago
via Eclipse Bugzilla by dj.houghton, 1 year ago
via ws-users by mith86, 1 year ago
For input string: "Client"
via ws-users by mith86, 1 year ago
For input string: "Client"
java.lang.NumberFormatException: For input string: "ABC"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:492)
at java.lang.Integer.parseInt(Integer.java:527)
at com.astrazeneca.vardict.Utils.toInt(Utils.java:75)
at com.astrazeneca.vardict.VarDict.toRegions(VarDict.java:126)
at com.astrazeneca.vardict.VarDict.start(VarDict.java:64)
at com.astrazeneca.vardict.Main.run(Main.java:134)
at com.astrazeneca.vardict.Main.main(Main.java:25)

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