Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Samebug tips

  1. ,
    Expert tip

    Thrown to indicate that an index of some sort (such as to an array, to a string, or to a vector) is out of range. Applications can subclass this class to indicate similar exceptions.

  2. ,

    Thrown if trying to access an index which is out of bounds on objects like String, Array, or Vector. Any negative integer less than or equal to -1 and positive integer greater than or equal to the size of the object is an index which would be out of bounds

Solutions on the web

via GitHub by luckcoolla
, 1 year ago
Invalid index 0, size is 0
via Stack Overflow by Zhafirin
, 1 year ago
via GitHub by soeiner
, 1 year ago
Invalid index 1, size is 1
via Stack Overflow by Iori
, 2 years ago
via Stack Overflow by user3788866
, 2 years ago
Invalid index 0, size is 0
java.lang.IndexOutOfBoundsException: Invalid index 0, size is 0	at java.util.ArrayList.throwIndexOutOfBoundsException(	at java.util.ArrayList.get(	at$MultiSegmentBase.getSegmentTimeUs(	at$MultiSegmentRepresentation.getTimeUs(	at$PeriodSeekInfo.createPeriodSeekInfo(	at	at	at	at$ManifestCallback.onLoadCompleted(	at$ManifestCallback.onLoadCompleted(	at$LoadTask.handleMessage(	at android.os.Handler.dispatchMessage(	at android.os.Looper.loop(	at	at