java.lang.NumberFormatException: For input string: "12.0"

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You try to parse a String that contains non-numeric characters to an int. The string must contain decimal characters only, optionally beginning with a + or - sign.

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via Eclipse Bugzilla by sbalusani, 1 year ago
via Eclipse Bugzilla by dj.houghton, 1 year ago
via ws-users by mith86, 1 year ago
For input string: "Client"
java.lang.NumberFormatException: For input string: "12.0"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:580)
at java.lang.Integer.parseInt(Integer.java:615)
at routines.system.ParserUtils.parseTo_int(ParserUtils.java:122)
at routines.system.ParserUtils.parseTo_Integer(ParserUtils.java:137)
at bigdata.forecast_ftp_write_prachi_0_1.Forecast_FTP_Write_Prachi.tSalesforceInput_1Process(Forecast_FTP_Write_Prachi.java:1257)
at bigdata.forecast_ftp_write_prachi_0_1.Forecast_FTP_Write_Prachi.runJobInTOS(Forecast_FTP_Write_Prachi.java:3304)
at bigdata.forecast_ftp_write_prachi_0_1.Forecast_FTP_Write_Prachi.main(Forecast_FTP_Write_Prachi.java:3161)

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