java.lang.NumberFormatException: For input string: "1111111111111111111111111111111111111111111111111111111111111111"

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Root Cause Analysis

  1. java.lang.NumberFormatException

    For input string: "1111111111111111111111111111111111111111111111111111111111111111"

    at java.lang.NumberFormatException.forInputString()
  2. Java RT
    Long.parseLong
    1. java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    2. java.lang.Long.parseLong(Long.java:592)
    2 frames