java.lang.IllegalArgumentException: Invalid UUID string:

Searched on Google with the first line of a JAVA stack trace?

We can recommend more relevant solutions and speed up debugging when you paste your entire stack trace with the exception message. Try a sample exception.

Recommended solutions based on your search

Solutions on the web

via Stack Overflow by mrusinak
, 1 year ago
via Stack Overflow by Alexander Supertramp
, 2 years ago
Invalid UUID string: 00000000-00000000-00000000-00000000
via GitHub by wsetzer
, 1 year ago
Invalid UUID string: affe50759da749c1952dc0e69d906699
java.lang.IllegalArgumentException: Invalid UUID string:
at java.util.UUID.fromString(
at example.EventId$$anonfun$1.apply(EventId.scala:10)
at example.EventId$$anonfun$1.apply(EventId.scala:10)
at com.trueaccord.scalapb.TypeMapper$$anon$1.toCustom(TypeMapper.scala:24)
at example.Event.Event$.defaultInstance$lzycompute(Event.scala:71)
at example.Event.Event$.defaultInstance(Event.scala:70)
at example.Event.Event$.defaultInstance(Event.scala:58)
at com.trueaccord.scalapb.LiteParser$.parseFrom(LiteParser.scala:9)
at com.trueaccord.scalapb.GeneratedMessageCompanion$class.parseFrom(GeneratedMessageCompanion.scala:103)
at example.Event.Event$.parseFrom(Event.scala:58)

Users with the same issue

2 times, 1 month ago
Once, 7 months ago
Once, 1 year ago
Once, 1 year ago
Samebug visitor profile picture
Unknown user
Once, 2 years ago
3 more bugmates

Know the solutions? Share your knowledge to help other developers to debug faster.