org.json.JSONException

End of input at character 0 of

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The json is invalid or you try to map to a different model.

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Solutions on the web1040

  • via GitHub by bastei
    , 4 months ago
    End of input at character 0 of
  • End of input at character 0 of
  • via GitHub by door43app
    , 1 year ago
    End of input at character 0 of
  • Stack trace

    • org.json.JSONException: End of input at character 0 of at org.json.JSONTokener.syntaxError(JSONTokener.java:446) at org.json.JSONTokener.nextValue(JSONTokener.java:93) at org.json.JSONObject.<init>(JSONObject.java:154) at org.json.JSONObject.<init>(JSONObject.java:171) at com.adwhirl.AdWhirlManager.parseConfigurationString(AdWhirlManager.java:290) at com.adwhirl.AdWhirlManager.fetchConfig(AdWhirlManager.java:257) at com.adwhirl.AdWhirlLayout$InitRunnable.run(AdWhirlLayout.java:367) at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:444) at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:306) at java.util.concurrent.FutureTask.run(FutureTask.java:138) at java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.access$201(ScheduledThreadPoolExecutor.java:153) at java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.run(ScheduledThreadPoolExecutor.java:267) at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1088) at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:581) at java.lang.Thread.run(Thread.java:1019)

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